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Q.Define Simple Harmonic Motion. Derive an expression for displacement, velocity and acceleration of a particle executing S.H.M.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2024Subjective· 5mImportance★★★★★
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SHM is periodic motion with acceleration proportional to and directed opposite to displacement; its displacement, velocity and acceleration as functions of time are x = A sin(wt+phi), v = Aw cos(wt+phi), and a = -w^2 x.

Definition: Simple Harmonic Motion (SHM) is a type of periodic motion in which the restoring force (and hence the acceleration) acting on the particle is always directed towards a fixed mean (equilibrium) position, and is directly proportional in magnitude to the displacement of the particle from that mean position. Mathematically, the defining condition is:

a=−ω2xa = -\omega^2 x

where ω\omega is a constant called the angular frequency.

Derivation of displacement: Since a=d2xdt2=−ω2xa = \dfrac{d^2x}{dt^2} = -\omega^2 x, this is a second-order linear differential equation whose general solution is:

x(t)=Asin⁡(ωt+ϕ)x(t) = A\sin(\omega t + \phi)

where AA is the amplitude (maximum displacement) and ϕ\phi is the initial phase (phase constant), fixed by initial conditions.

Derivation of velocity: Velocity is the time derivative of displacement:

v=dxdt=Aωcos⁡(ωt+ϕ)v = \dfrac{dx}{dt} = A\omega\cos(\omega t+\phi)

This can also be written in terms of displacement as v=ωA2−x2v = \omega\sqrt{A^2 - x^2}, showing velocity is maximum (vmax=Aωv_{max} = A\omega) at the mean position (x=0x=0) and zero at the extremes (x=±Ax=\pm A).

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