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Q.Explain the following terms :

(i) Molarity
(ii) Molality
(iii) Normality
(iv) Mole fraction
(v) Parts Per Million (PPM). OR State and explain Raoult's law in case of volatile solute.
Jammu Kashmir JkboseJKBOSE Class 12 Annual Regular Examination 2018Subjective· 5mImportance★★★★★
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Molarity, molality, normality, mole fraction and ppm are different ways of expressing the concentration of a solution — they differ in whether they use the volume of the solution, the mass of the solvent, or the total amount of all species present as the reference quantity.

  1. Molarity (M): the number of moles of solute dissolved per litre (dm³) of solution: M = n(solute) / V(solution in L). Unit: mol/L. Since the volume of a solution expands slightly on heating, molarity changes (slightly decreases) with rising temperature.
  2. Molality (m): the number of moles of solute per kilogram of solvent (not solution): m = n(solute) / w(solvent in kg). Unit: mol/kg. Because mass is unaffected by temperature, molality is a temperature-independent measure, and so is preferred wherever precise physical-property work (like boiling-point elevation or freezing-point depression) is done.
  3. Normality (N): the number of gram-equivalents of solute dissolved per litre of solution: N = (no. of gram-equivalents of solute) / V(solution in L), where gram-equivalents = mass of solute ÷ equivalent weight. Normality is related to molarity by N = M × n-factor, the n-factor being the basicity (for acids), acidity (for bases), or the number of electrons/charge transferred (for redox reactions).
  4. Mole fraction (x): the ratio of the moles of one component to the total moles of all components present. For a binary solution of A and B: x(A) = n(A) / [n(A) + n(B)], and x(A) + x(B) = 1. It is dimensionless and temperature-independent, and is the variable used in Raoult's law.
  5. Parts per million (ppm): used when a solute is present in very small (trace) amounts — it expresses the parts of solute present per million parts of the solution (by mass, volume, or moles): ppm = (mass of solute / mass of solution) × 10⁶. …

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