Skip to content
Question of 131

Q.Molarity of the liquid HCl if density of the solution is 1.17 g/cc is :

(a) 36.5
(b) 18.5
(c) 32.05
(d) 42.10
Jammu Kashmir JkboseJKBOSE Class 12 Annual Regular Examination 2024MCQ· 1mImportance★★★★★
0% · 0/131 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Treating the liquid as pure HCl (100% by mass), Molarity = (1000 × density)/(molar mass) = (1000 × 1.17)/36.5 = 32.05 mol/L.

Molarity (M) of a pure liquid (100% strength, no separate solvent) is obtained directly from its density and molar mass, since 1 litre of the liquid weighs (1000 × density) grams, all of which is HCl:

M = (1000 × density) / (molar mass of HCl)

Given: density = 1.17 g/cc = 1.17 g/mL, molar mass of HCl = 1 + 35.5 = 36.5 g/mol.

M = (1000 × 1.17) / 36.5 = 1170 / 36.5 = 32.05 mol/L

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.