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Exercises · 5.12

Q.Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K–1 mol–1).

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Step 1 – Write the ideal gas equation solved for TT

pV=nRT  ⟹  T=pVnRpV = nRT \implies T = \frac{pV}{nR}

Step 2 – Substitute the data

p=3.32 bar,V=5 dm3,n=4.0 mol,R=0.083 bar dm3K−1mol−1p = 3.32\ \text{bar}, \quad V = 5\ \text{dm}^3, \quad n = 4.0\ \text{mol}, \quad R = 0.083\ \text{bar dm}^3\text{K}^{-1}\text{mol}^{-1} …

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