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Q.A system absorbs 701 J of heat and 394 J work is done by it. Calculate the internal energy change of the system.
Jharkhand JacJAC Intermediate Board (1st Year) 2022Subjective· 3mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Using the first law, Delta U = q + w, with q = +701 J (heat absorbed BY the system) and w = -394 J (work done BY the system, so work done ON the system is negative): Delta U = 701 - 394 = 307 J.
First law of thermodynamics: Delta U = q + w, where q is heat given TO the system (positive if absorbed by the system) and w is work done ON the system (positive if work is done on the system by the surroundings, negative if the system does work on the surroundings).
Given:
- Heat absorbed by the system, q = +701 J (positive, since the system absorbs/gains heat)
- Work done BY the system on the surroundings = 394 J. Since this work is done by the system (not on it), w = -394 J in the sign convention above.
Calculation:
Delta U = q + w = 701 J + (-394 J) = 701 - 394 = 307 J
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