Skip to content
Question of 87

Q.What happens when -

(a) Acetaldehyde is treated with hydrazine?
(b) Ethyl iodide reacts with alcoholic KOH solution?
Jharkhand JacJAC Intermediate Board 2020Subjective· 2mImportance★★★★★
0% · 0/87 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

(a) A carbonyl compound condenses with hydrazine (a nitrogen nucleophile) to give a hydrazone. (b) Alcoholic (not aqueous) KOH acts as a base rather than a nucleophile, favouring elimination of HI over substitution.

(a) Acetaldehyde treated with hydrazine:

CH3CHO + H2N-NH2 --> CH3CH=N-NH2 + H2O

The -NH2 nitrogen of hydrazine (a good nucleophile) attacks the electrophilic carbonyl carbon of acetaldehyde, forming a tetrahedral intermediate that then loses water to give the C=N double bond of the hydrazone, acetaldehyde hydrazone.

(b) Ethyl iodide with alcoholic KOH:

CH3CH2I + KOH (alc.) --> CH2=CH2 + KI + H2O

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.