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NCERT Exemplar · Q29

Q.If f(x)=ax+bf(x) = ax + b, where aa and bb are integers, f(−1)=−5f(-1) = -5 and f(3)=3f(3) = 3, then aa and bb are equal to
(A) a=−3, b=−1a = -3,\ b = -1
(B) a=2, b=−3a = 2,\ b = -3
(C) a=0, b=2a = 0,\ b = 2
(D) a=2, b=3a = 2,\ b = 3

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We are given a linear function f(x)=ax+bf(x)=ax+b with two conditions f(−1)=−5f(-1)=-5 and f(3)=3f(3)=3. Substituting these gives two equations in aa and bb; solving them yields a=2a=2 and b=−3b=-3, which matches option (B).

The core idea here is function evaluation: plugging a specific xx into f(x)f(x) gives a corresponding output. Since ff is linear, two such input-output pairs are enough to determine the constants aa (the slope) and bb (the yy-intercept). This is exactly like finding the equation of a straight line given two points.

Let’s work through it step by step.

  1. Write the equations from the given conditions. For f(−1)=−5f(-1) = -5:

a(−1)+b=−5⇒−a+b=−5.(1)a(-1) + b = -5 \quad \Rightarrow \quad -a + b = -5. \qquad(1)

For f(3)=3f(3) = 3:

a(3)+b=3⇒3a+b=3.(2)a(3) + b = 3 \quad \Rightarrow \quad 3a + b = 3. \qquad(2)

  1. Solve the system of linear equations. Subtract equation (1) from equation (2) to eliminate bb:

(3a+b)−(−a+b)=3−(−5)(3a + b) - (-a + b) = 3 - (-5)

3a+b+a−b=3+53a + b + a - b = 3 + 5

4a=8⇒a=2.4a = 8 \quad \Rightarrow \quad a = 2.

  1. Find bb using either equation. Substitute a=2a=2 into equation (2): 3(2)+b=3⇒6+b=3⇒b=−3.3(2) + b = 3 \quad \Rightarrow \quad 6 + b = 3 \quad \Rightarrow \quad b = -3. …

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