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Q.State Ampere's circuital law and arrive at the expression for the magnetic field near a straight infinite current carrying wire.

Karnataka PUCKarnataka II PUC Board 2018Subjective· 3mImportance★★★★★
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∮B⃗⋅dl⃗=μ0Ienc\oint \vec B\cdot d\vec l = \mu_0 I_{enc}; for a long straight wire this gives B=μ0I2πrB = \dfrac{\mu_0 I}{2\pi r}.

Statement (Ampere's circuital law): The line integral of the magnetic field B⃗\vec B around any closed loop equals μ0\mu_0 times the net current IencI_{enc} passing through the loop:

∮B⃗⋅dl⃗=μ0Ienc.\oint \vec B\cdot d\vec l = \mu_0 I_{enc}.

Field near a long straight wire: By symmetry the field lines are concentric circles around the wire, with B⃗\vec B constant in magnitude and tangential on a circle of radius rr. Choosing such a circle as the Amperian loop: …

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