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Q.Analyse the graph given below and answer the following questions : [graph of ionisation enthalpy vs atomic number Z with values Li 520, Be 899, B 801, C 1086, N 1402, O 1314, F 1681, Ne 2080]

(i) Identify the elements showing deviation in ionisation enthalpy from the general trend.
(1)
(ii) Explain the reason for deviation in each case. (2)
Kerala DhseKerala DHSE Plus One Board 2025Subjective· 3mImportance★★★★★
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First ionisation enthalpy across Period 2 (Li to Ne) showing the dips at B and O
First ionisation enthalpy across Period 2 (Li to Ne) showing the dips at B and O

B and O dip below the trend: Be's filled 2s and N's half-filled 2p are extra stable, so B and O (next along) lose an electron more easily.

  1. Along period 2 the first ionisation enthalpy generally increases (Li -> Ne) because nuclear charge rises while the shell stays the same. Two elements fall below their expected values: Boron (below Be) and Oxygen (below N).
  2. Reasons:
  • Beryllium (2s2) has a completely filled 2s subshell, which is extra stable, so its IE is unexpectedly high; Boron (2s2 2p1) can lose its single, higher-energy 2p electron more easily, so B's IE dips below Be. …

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