Skip to content
Exercise 9.1 · Q10

Q.The slope of a line is double of the slope of another line. If tangent of the angle between them is 13\dfrac{1}{3}, find the slopes of the lines.

Kerala DhseTextbookSubjective· 3mImportance★★★★★est
7% · 10/145 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Let the slopes be mm and 2m2m. Solving ∣m1+2m2∣=13\left|\dfrac{m}{1+2m^2}\right| = \dfrac13 for both signs gives four valid slope pairs: (1,2)(1,2), (12,1)\left(\dfrac12, 1\right), (−1,−2)(-1,-2), and (−12,−1)\left(-\dfrac12,-1\right).

Setting up the equation

Let the smaller slope be mm, so the other slope is 2m2m (double of it). If θ\theta is the angle between the two lines, the standard formula gives

tan⁡θ=∣m2−m11+m1m2∣=∣2m−m1+m(2m)∣=∣m1+2m2∣.\tan\theta = \left|\frac{m_2 - m_1}{1 + m_1m_2}\right| = \left|\frac{2m-m}{1+m(2m)}\right| = \left|\frac{m}{1+2m^2}\right|.

We are told tan⁡θ=13\tan\theta = \dfrac13, so

∣m1+2m2∣=13.\left|\frac{m}{1+2m^2}\right| = \frac13.

Because of the absolute value, this splits into two cases.

Case 1: m1+2m2=13\dfrac{m}{1+2m^2} = \dfrac13

Cross-multiplying:

3m=1+2m2⟹2m2−3m+1=0.3m = 1 + 2m^2 \quad\Longrightarrow\quad 2m^2 - 3m + 1 = 0.

Factoring:

(2m−1)(m−1)=0⟹m=1 or m=12.(2m-1)(m-1) = 0 \quad\Longrightarrow\quad m = 1 \ \text{or}\ m = \frac12.

Case 2: m1+2m2=−13\dfrac{m}{1+2m^2} = -\dfrac13

Cross-multiplying:

3m=−1−2m2⟹2m2+3m+1=0.3m = -1 - 2m^2 \quad\Longrightarrow\quad 2m^2 + 3m + 1 = 0.

Factoring:

(2m+1)(m+1)=0⟹m=−1 or m=−12.(2m+1)(m+1) = 0 \quad\Longrightarrow\quad m = -1 \ \text{or}\ m = -\frac12.

Reading off the slope pairs

Recall the two slopes are mm and 2m2m. Each value of mm found above gives one genuine, distinct pair:

| mm | Slopes (m,2m)(m, 2m) | …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.