Question of 53
Q.Due to capillary action, water will rise inside a glass tube.
(a) The angle of contact in this case is
(i) Acute
(ii) Obtuse
(iii) 90°
(iv) Zero
(b) Obtain an expression for the rise of liquid in the tube.
(c) Water rises to different heights in glass tubes of different radii. Give reason.
Kerala DhseKerala DHSE Plus One Board 2023Subjective· 5mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Water wets clean glass, giving an angle of contact of essentially 0°. Balancing the vertical component of the surface-tension force around the tube's circumference against the weight of the raised liquid column gives h = 2Tcosθ/(rρg). Because h is inversely proportional to the tube radius r, a narrower capillary produces a taller rise, which is exactly why the same liquid climbs to different heights in tubes of different bore.
- Angle of contact for water and glass The angle of contact θ is the angle between the tangent to the liquid surface at the point of contact and the solid surface, measured inside the liquid. For pure water on a clean glass surface, the liquid wets the glass completely (the meniscus is strongly concave upward), and the angle of contact is very close to θ ≈ 0°
- Derivation of the height of capillary rise Consider a capillary tube of internal radius r dipped vertically into water of surface tension T and density ρ, with angle of contact θ. Surface tension acts along the circumference of the liquid surface where it meets the glass, tangentially to the liquid surface, and pulls the liquid upward. The force of surface tension along the whole circumference (length 2πr) is T·(2πr), acting at angle θ to the vertical wall of the tube. Its vertical (upward) component is what supports the raised column: Upward force = T cosθ × 2πr This force supports the weight of the liquid column of height h that has risen inside the tube (radius r, so cross-sectional area πr²): Weight of raised liquid = (volume)(density)(g) = (πr²h)(ρ)(g) At equilibrium, the upward surface-tension force balances this weight: T cosθ × 2πr = πr²hρg Cancelling πr from both sides: …
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