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Q.(a) What is capillary rise?

(b) With the help of a diagram, derive an expression for capillary rise inside a narrow tube of radius r.
(c) Mercury has an angle of contact equal to 140° with soda lime glass. A narrow tube of radius 2 mm, made of this glass is dipped in a trough containing mercury. By what amount does the mercury dip down in the tube relative to the liquid surface outside? (Surface tension of mercury S = 0.456 N m⁻¹, Density of mercury ρ = 13.6 × 10³ kg m⁻³)
Kerala DhseKerala DHSE Plus One Board 2026Subjective· 5mImportance★★★★★
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Capillary rise h = 2 S cos theta/(rho g r); for mercury with contact angle 140 degrees the result is negative, so mercury dips by about 2.6 mm.

Capillary rise schematic picture narrow tube immersed
Capillary rise schematic picture narrow tube immersed
  1. Capillary rise (capillarity) is the phenomenon of rise (or fall) of a liquid inside a narrow tube (capillary) when it is dipped in the liquid, caused by surface tension. Liquids that wet the tube (like water) rise; liquids that do not wet it (like mercury) are depressed.
  2. Derivation for capillary rise in a tube of radius r: The liquid rises until the weight of the raised column is supported by the vertical component of the surface tension force acting around the circle of contact. Upward force from surface tension = S cos theta x (circumference) = S cos theta x 2 pi r. Weight of the liquid column of height h = (mass) x g = (rho x pi r^2 h) x g. Equating: S cos theta x 2 pi r = rho pi r^2 h g. Solving for h: h = 2 S cos theta / (rho g r). …

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