Q.In fibrous proteins, polypeptide chains are held together by _______. (Note: one or more of the following options may be correct.)
🔒You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Biochemical Bonds
Biochemical Bonds: The Glue That Holds Life Together
Imagine you're building with LEGO bricks. Some bricks click together tightly and never come apart unless you really yank them. Others snap together lightly and can be pulled apart with a gentle tug. Some bricks don't even click — they just stick because of static cling or magnetism.
Biochemical bonds are exactly like that. They are the forces that hold atoms together inside the molecules of your body — your DNA, proteins, fats, and carbohydrates. Without these bonds, you'd literally fall apart into a pile of individual atoms.
The Core Idea
Atoms bond because being bonded is more stable (lower energy) than being alone. Think of it like this: a single atom is like a person standing alone in a cold room. Bonding is like huddling together for warmth — you lose some freedom of movement, but you gain stability.
In biochemistry, we care about four main types of bonds. They differ in strength, how they form, and what they do in living systems.
1. Covalent Bonds — The Strong, Permanent LEGO Clicks
This is the strongest bond in biology. Two atoms share electrons — like two people holding the same umbrella. Each atom contributes one or more electrons, and they both "own" the pair.
Key properties:
- Very strong (100–400 kJ/mol)
- Forms the backbone of all biomolecules
- Takes a lot of energy (or enzymes) to break
Where you find it:
- The carbon-carbon bonds in your DNA's sugar-phosphate backbone
- The peptide bonds linking amino acids into proteins
- The bonds within a glucose molecule
A single covalent bond shares 2 electrons. A double bond shares 4. Triple bonds are rare in biology but exist (e.g., in cyanide).
2. Ionic Bonds — The Static Cling of Opposites
Some atoms steal electrons from others. When that happens, one atom becomes positively charged (lost an electron) and the other becomes negatively charged (gained one). Opposite charges attract — that's an ionic bond.
Key properties:
- Moderate strength (5–100 kJ/mol in dry conditions)
- Very weak in water (because water molecules get in between)
- Easily broken by changes in pH or salt concentration
Where you find it:
- In salt bridges that help proteins fold into their correct shape
- Between the phosphate groups of DNA and positively charged proteins (histones)
Ionic bonds are often called "bonds" but in water they behave more like attractions. Don't confuse them with covalent bonds — they're much weaker in biological fluids.
3. Hydrogen Bonds — The Gentle, Reversible Magnets
This is the most important weak bond in biology. A hydrogen atom that's already covalently bonded to an electronegative atom (like oxygen or nitrogen) gets a slight positive charge. It then gets attracted to another electronegative atom nearby.
Think of it like a weak magnet — it holds things together but can be easily undone.
Key properties:
- Weak individually (5–30 kJ/mol)
- But many together can be very strong
- Easily broken by heat or changes in pH
- Directional — they only work when atoms are properly aligned
Where you find it:
- Between the two strands of DNA (this is what holds the double helix together)
- In protein folding (between amino acids in the backbone)
- Between water molecules (giving water its unique properties)
Hydrogen bonds are the reason DNA can unzip for replication. If DNA used covalent bonds between strands, it would be impossible to separate without destroying the molecule.
4. Van der Waals Interactions — The Fleeting, Accidental Touches
Even neutral atoms have temporary, uneven distributions of electrons. These create tiny, momentary charges that attract nearby atoms. It's like two people accidentally brushing shoulders in a crowd — brief, weak, but real.
Key properties:
- Extremely weak (0.5–5 kJ/mol per interaction)
- Only work when atoms are very close (within 0.3–0.4 nm)
- Add up significantly when many atoms are packed together
Where you find it:
- In the hydrophobic core of proteins (where oily amino acids pack tightly)
- Between lipid tails in cell membranes
- In enzyme-substrate binding (helps "grip" the substrate)
Putting It All Together: A Biological Example
Consider a protein in your body. It's a long chain of amino acids held together by covalent peptide bonds. That chain then folds into a specific shape. The folding is guided by:
- Hydrogen bonds between backbone atoms (forming alpha helices and beta sheets)
- Ionic bonds between charged side chains …
Why this formula?
Biochemical Bonds: Why the Key Formulas Hold
Biochemical bonds are the forces that hold atoms together in biomolecules. The key formulas come from electrostatics and quantum mechanics — not from biology itself. Let's break down the why behind the most important ones.
1. Ionic Bond Energy: Coulomb's Law
Formula:
E=rk⋅q1⋅q2
Why it holds:
- Opposite charges attract — this is a fundamental law of physics (Coulomb's law).
- In a biochemical context, consider a sodium ion (Na+) and a chloride ion (Cl−). The energy released when they come together is directly proportional to the product of their charges (q1q2) and inversely proportional to the distance (r) between them.
- The constant k accounts for the medium (water vs. vacuum). In water, the effective force is weaker because water molecules partially shield the charges — this is why ionic bonds in biology are often weaker in aqueous environments.
Key insight: The formula is not arbitrary — it's derived from the inverse-square law of electrostatics, integrated over the distance the charges move toward each other.
2. Covalent Bond Energy: The Morse Potential (Approximation)
Formula (simplified):
E=De(1−e−a(r−r0))2
Why it holds:
-
Covalent bonds arise from shared electrons between atoms. The energy is not a simple inverse-square law because electrons are delocalized.
-
The Morse potential is an empirical formula that captures two key observations:
- At equilibrium distance (r0): Energy is minimum (E=0 in this form).
- If atoms are pulled apart (r→∞): Energy approaches De (the bond dissociation energy).
- If atoms are pushed too close (r→0): Energy skyrockets due to Pauli repulsion (electrons can't occupy the same space).
-
The exponential term e−a(r−r0) models the rapid drop in attractive force as distance increases — this comes from quantum mechanical overlap of electron clouds.
Key insight: The formula is a curve fit to quantum mechanical calculations, not a first-principles derivation. But it works because it respects the physics: attraction at long range, repulsion at short range, and a stable minimum.
3. Hydrogen Bond Energy: Dipole-Dipole Interaction
Formula (approximate):
E≈−4πϵ0r32μ1μ2⋅cosθ
Why it holds:
- A hydrogen bond (e.g., between water molecules) is not a true bond — it's a strong dipole-dipole interaction.
- The dipole moment (μ) arises because oxygen is more electronegative than hydrogen, creating partial charges (δ+ and δ−).
- The energy depends on:
- Strength of dipoles (μ1μ2)
- Distance (r) — falls off as 1/r3, much faster than ionic bonds (1/r)
- Orientation (cosθ) — strongest when dipoles are aligned head-to-tail
Key insight: The 1/r3 dependence comes from the derivative of the dipole field. Unlike point charges, dipoles have a field that decays faster — this is why hydrogen bonds are directional and weaker than covalent bonds.
4. Van der Waals Interaction: Lennard-Jones Potential
Formula:
E=4ϵ[(rσ)12−(rσ)6]
Why it holds:
- Van der Waals forces arise from temporary fluctuations in electron distribution — even nonpolar molecules have instantaneous dipoles. …
The key idea is that fibrous proteins, like collagen or keratin, rely on a few dominant, specific interactions to hold their polypeptide chains together — not just any weak intermolecular force.
- Disulphide linkages (−S−S−) form covalent bonds between cysteine residues, providing permanent, strong cross-links in proteins like keratin.
- Hydrogen bonds occur between the N−H and C=O groups of the polypeptide backbone, stabilising the repeating secondary structures (e.g., the coiled-coil in keratin, the triple helix in collagen) that are characteristic of fibrous proteins. …
Fibrous proteins are held together mainly by hydrogen bonds between backbone amide groups and disulphide linkages between cysteine residues — so the correct options are (ii) and (iv).
The question asks what holds polypeptide chains together in fibrous proteins. Fibrous proteins — like collagen, keratin, and myosin — are structural proteins with long, rod-like shapes. Their strength and stability come from two dominant interactions.
-
Hydrogen bonds are the backbone of secondary structure. In α-keratin (a fibrous protein), the α-helices are stabilized by hydrogen bonds between the carbonyl oxygen of one residue and the amide hydrogen of another, four residues away. In collagen, hydrogen bonds form between the three polypeptide strands of the triple helix. Without hydrogen bonds, the chains would simply drift apart. So (iv) is correct.
-
Disulphide linkages are covalent bonds between the sulfur atoms of two cysteine residues. These are especially important in keratin — the protein in hair, nails, and skin. The more disulphide cross-links, the harder the material (think horn vs. soft fur). So (ii) is correct.
-
Van der Waals forces (i) are weak, non-specific attractions that occur between all atoms when they are close together. They exist in every protein, but they are far too weak and non-directional to be the defining force holding fibrous-protein chains together, so this is not the answer the question is looking for. …
Method: Conceptual Elimination by Bond Type & Protein Structure
Step 1 – Recall the defining feature of fibrous proteins
Fibrous proteins (e.g., collagen, keratin, elastin) are structural — they form long, parallel polypeptide chains that are tightly packed to provide strength and elasticity.
Step 2 – List the bonds that stabilize any protein structure
- Primary structure: peptide bonds (covalent)
- Secondary & tertiary structure: hydrogen bonds, disulphide bridges, ionic (electrostatic) interactions, van der Waals forces
- Quaternary structure: same set of non-covalent bonds + sometimes disulphide links
Step 3 – Identify which bonds are especially important in fibrous proteins
Fibrous proteins rely heavily on inter-chain stability. The key stabilizers are:
- Hydrogen bonds — between N–H and C=O groups of adjacent chains (e.g., in collagen triple helix)
- Disulphide linkages — covalent cross-links between cysteine residues (e.g., in keratin)
- Electrostatic forces — ionic attractions between charged side chains (e.g., in silk fibroin) …
Here are the common mistakes students make on this question about Biochemical Bonds in Fibrous Proteins, along with how to avoid each.
Mistake 1: Selecting only one option (e.g., only hydrogen bonds)
Why it happens:
Students often memorize that fibrous proteins (like collagen, keratin, or silk fibroin) are stabilized by hydrogen bonds between polypeptide chains. They stop there, forgetting that fibrous proteins are multiply stabilized.
How to avoid:
Always recall the structural hierarchy of fibrous proteins. They are not just held by one type of bond. In a typical fibrous protein:
- Hydrogen bonds (between N–H and C=O groups) give strength and elasticity.
- Disulphide linkages (covalent –S–S– bonds between cysteine residues) provide permanent cross-linking (e.g., in keratin).
- Electrostatic forces (ionic bonds between charged side chains) also contribute.
- van der Waals forces (hydrophobic interactions) are present but are weak and not the primary stabilizers.
Key takeaway: The question says “one or more options may be correct.” Always check all options for relevance.
Mistake 2: Including van der Waals forces as a primary stabilizer
Why it happens:
Students think “all non-covalent interactions matter equally.” In fibrous proteins, van der Waals forces are present but are not the main forces holding polypeptide chains together — they are too weak and non-directional.
How to avoid:
Remember the relative strength of interactions in protein structure:
- Strongest: Covalent bonds (disulphide linkages)
- Moderate: Hydrogen bonds, electrostatic forces
- Weakest: van der Waals forces
For fibrous proteins, the primary stabilizers are hydrogen bonds, disulphide bonds, and electrostatic attractions. van der Waals forces are secondary and not exam-worthy as a “holding” force here.
Mistake 3: Confusing fibrous proteins with globular proteins
Why it happens:
Students mix up the bonding patterns. In globular proteins, hydrophobic interactions (van der Waals) are crucial for folding. In fibrous proteins, the chains are extended and parallel — so inter-chain hydrogen bonds dominate.
How to avoid:
Use a simple mnemonic:
- Fibrous → F for Filamentous, Forces = Hydrogen, Disulphide, Electrostatic.
- Globular → G for Globular, Gets Van der Waals (hydrophobic core).
Mistake 4: Forgetting that disulphide linkages are covalent and permanent
Why it happens: …
- KEAM 2025Set eng-2025-04294 marksMCQQ.Peptide on hydrolysis gives (A) glucose (B) fatty acids (C) amino acids (D) ribose sugar, H3PO4 and base (E) heterocyclic base and sugar
›Reveal solutionSolution
A peptide is built from amino acids linked by peptide (amide) bonds, so its hydrolysis regenerates amino acids.
Peptides and proteins are made up of α-amino acid residues connected through peptide (amide) linkages (-CO-NH-). On hydrolysis (acidic, basic or enzymatic), these amide bonds are cleaved and the molecule breaks down into its constituent amino acids. (Glucose comes …
- KEAM 2024Set eng-2024-06084 marksMCQQ.Which of the following statement is correct? (A) Sucrose is laevorotatory. (B) Fructose is a disaccharide. (C) Sucrose on hydrolysis gives D(+)-glucose only. (D) Sucrose is made up of a glycosidic linkage between C1 of α-D-glucose and C2 of β-D-Fructose. (E) Sucrose is a reducing sugar.
›Reveal solutionSolution
Sucrose links C1 of α-D-glucose to C2 of β-D-fructose; both anomeric carbons are involved, so it is non-reducing and dextrorotatory. Only statement (D) is correct.
Checking each statement:
- (A) Sucrose is dextrorotatory ([α]D=+66.5∘), not laevorotatory — false.
- (B) Fructose is a monosaccharide, not a disaccharide — false.
- (C) Hydrolysis of sucrose gives both D(+)-glucose and D(−)-fructose (invert sugar), not glucose only — false. …
🎓Unlock everything free for 14 days
- ✓Full step-by-step solutions
- ✓Concept-first explanations
- ✓Methods, shortcuts & mistakes
- ✓PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.