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Q.Using elementary row operations, find the inverse of the matrix [[1, 2], [2, -1]]. (Scores : 3)

Kerala DhseKerala DHSE Plus Two Board 2018Subjective· 3mImportance★★★★★
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Augment AA with the identity matrix and use row operations to reduce the left block to II; the right block becomes A−1A^{-1}.

We want the inverse of A=(122−1)A = \begin{pmatrix} 1 & 2 \\ 2 & -1 \end{pmatrix}.

Write [A∣I][A \mid I]:

(12∣102−1∣01)\begin{pmatrix} 1 & 2 & \big| & 1 & 0 \\ 2 & -1 & \big| & 0 & 1 \end{pmatrix}

Step 1: R2→R2−2R1R_2 \to R_2 - 2R_1:

(12∣100−5∣−21)\begin{pmatrix} 1 & 2 & \big| & 1 & 0 \\ 0 & -5 & \big| & -2 & 1 \end{pmatrix}

Step 2: R2→R2÷(−5)R_2 \to R_2 \div (-5):

(12∣1001∣2/5−1/5)\begin{pmatrix} 1 & 2 & \big| & 1 & 0 \\ 0 & 1 & \big| & 2/5 & -1/5 \end{pmatrix}

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