Question of 50
Q.(a) The electrical analog of mass is
(i) diode
(ii) capacitance
(iii) inductance
(iv) resistance (Score : 1)
(b) A 2 m long solenoid having diameter 6 cm and 2000 turns has a secondary of 500 turns wound closely near its mid-point. Calculate the mutual inductance between the two coils. (Scores : 2)
Kerala DhseKerala DHSE Plus Two Board 2016Subjective· 3mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Inductance L plays the role of mass in the electrical–mechanical oscillation analogy (since it opposes a change in current just as mass opposes a change in velocity); and for the described solenoid–coil system, the mutual inductance works out to about 1.78 mH.
- In the standard analogy between mechanical (spring–mass) SHM and electrical LC oscillations, energy stored in an inductor, (1/2)LI², plays the same role as kinetic energy, (1/2)mv², of a moving mass. Just as mass resists a change in velocity (inertia), an inductor resists a change in current (self-induced back-emf). So the electrical analogue of mass is inductance. (Correspondingly, 1/C plays the role of the spring constant, charge q plays the role of displacement x, and current I plays the role of velocity v.) Answer: (iii) inductance.
- The solenoid (primary) has length l = 2 m, diameter 6 cm so radius r = 3 cm = 0.03 m, and N₁ = 2000 turns; the secondary coil of N₂ = 500 turns is wound closely around the solenoid near its midpoint, so it links essentially the same cross-sectional area as the solenoid, A = πr². …
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