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Q.Two long co-axial solenoids of same length are shown below :

(a) Define mutual inductance of the pair of coils.
(1)
(b) Derive an expression for mutual inductance of two co-axial solenoids.
(2)
(c) Write the dimension of mutual inductance. (1)
Kerala DhseKerala DHSE Plus Two Board 2019Subjective· 4mImportance★★★★★
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Mutual inductance measures how much flux one coil links per unit current in a neighbouring coil; for two coaxial solenoids it works out to M=μ0N1N2πr12/lM=\mu_0N_1N_2\pi r_1^2/l, with the dimension of Henry, [ML2T−2A−2][ML^2T^{-2}A^{-2}].

  1. Definition of mutual inductance: Mutual inductance MM of a pair of coils is the magnetic flux linked with one coil (secondary) per unit current flowing in the other coil (primary): M=N2Φ2I1M = \dfrac{N_2\Phi_2}{I_1} Equivalently, it is defined via the emf induced in one coil due to the rate of change of current in the other: ε2=−MdI1dt\varepsilon_2 = -M\dfrac{dI_1}{dt}.
  2. Mutual inductance of two coaxial solenoids: Let solenoid 1 (inner, radius r1r_1, N1N_1 turns) be inside solenoid 2 (outer, radius r2r_2, N2N_2 turns), both of the same length ll. Pass a current I1I_1 through the inner solenoid 1. The magnetic field inside solenoid 1 is uniform: B1=μ0N1lI1B_1 = \mu_0 \dfrac{N_1}{l}I_1 This field exists only within radius r1r_1 (negligible field outside an ideal solenoid), so the flux linking each turn of the outer solenoid 2 (which surrounds solenoid 1) is just B1B_1 times the smaller cross-sectional area πr12\pi r_1^2: …

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