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Q.(A) The following is a choice question :

(a) If the focal length of a double convex lens is 12 cm and radii of curvatures of faces are 10 cm and 15 cm respectively, what is the refractive index of the lens ? (Scores : 2)
(b)
(i) Draw the ray diagram showing the formation of image by a compound microscope. (Scores : 2)
(ii) Show that in order to achieve large magnification in a compound microscope the magnitude of focal length of objective and eye piece should be small. (Scores : 3) OR (B)
(a) What is the structure of an optical fibre ? (Scores : 2)
(b) What is the principle used for transmitting audio and video signals using optical fibre ? Explain the principle. (Scores : 2)
(c) With the help of a neat diagram arrive at an expression for finding the refractive index of a prism. (Scores : 3)
Kerala DhseKerala DHSE Plus Two Board 2016Subjective· 7mImportance★★★★★
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Figure — Answered alternative (A)(b)(i) explicitly says 'Draw the ray diagram showing the formation of image by a compo
Figure — Answered alternative (A)(b)(i) explicitly says 'Draw the ray diagram showing the formation of image by a compo

The lens maker's formula gives n = 1.5 for the described double convex lens; and in a compound microscope, since the overall magnification M = (L/f₀)(D/f_e), making both the objective's and the eyepiece's focal lengths small is exactly what boosts the magnifying power.

(a) Lens maker's formula: 1/f = (n−1)(1/R₁ − 1/R₂)

For a double convex lens with light travelling left to right, using the standard sign convention, the first (left) surface is convex toward the incoming light so R₁ = +10 cm, and the second (right) surface is also convex outward (bulging away from the incident light, centre of curvature on the incident side) so R₂ = −15 cm.

1/12 = (n−1)(1/10 − 1/(−15)) = (n−1)(1/10 + 1/15)

1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6

1/12 = (n−1)/6

n − 1 = 6/12 = 0.5

n = 1.5

(b)(i) Ray-diagram description for a compound microscope: The object AB is placed just beyond the focal point F₀ of the objective lens (a short-focal-length convex lens). The objective forms a real, inverted and magnified image A′B′ a little inside the focal point F_e of the eyepiece. This intermediate image A′B′ then acts as the object for the eyepiece (a second convex lens, used essentially as a simple magnifier), which forms the final image A″B″ — virtual, further magnified, and inverted with respect to the original object — typically located at the near point of the eye (or at infinity in "normal adjustment"), which the observer views by placing the eye close to the eyepiece.

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