Skip to content
Question of 73

Q.(a) Speed of light in glass is 2 × 10^8 m/s. Refractive index of glass is ______. (Score : 1)

(b) For an equilateral prism made of a material of refractive index √2, find the angle of minimum deviation for a ray of monochromatic light. (Scores : 2)
(c) Draw the ray diagram of a simple microscope that uses a single convex lens. Derive an expression for its linear magnification. (Scores : 3)
Kerala DhseKerala DHSE Plus Two Board 2017Subjective· 6mImportance★★★★★
0% · 0/73 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →
Figure — Part (c) explicitly says 'Draw the ray diagram of a simple microscope that uses a single convex lens' (3 marks
Figure — Part (c) explicitly says 'Draw the ray diagram of a simple microscope that uses a single convex lens' (3 marks

(a) n = c/v = 1.5. (b) For an equilateral prism (A=60°) with n=√2, the minimum-deviation formula gives Dm = 30°. (c) A simple microscope is a single convex lens with the object inside its focal length; its angular magnification is m = 1 + D/f.

(a) Refractive index of glass

n=cv=3×1082×108=1.5n = \frac{c}{v} = \frac{3\times10^{8}}{2\times10^{8}} = 1.5

(b) Angle of minimum deviation for an equilateral prism

For an equilateral prism the prism angle A=60°A = 60°. The prism formula relating refractive index n, prism angle A and the angle of minimum deviation DmD_m is

n=sin⁡(A+Dm2)sin⁡(A2)n = \frac{\sin\left(\dfrac{A+D_m}{2}\right)}{\sin\left(\dfrac{A}{2}\right)}

Given n=2n=\sqrt{2} and A=60°A=60°, so A/2=30°A/2 = 30°, sin⁡30°=0.5\sin 30° = 0.5:

2=sin⁡(60+Dm2)0.5  ⟹  sin⁡(60+Dm2)=0.52=22=sin⁡45°\sqrt{2} = \frac{\sin\left(\dfrac{60+D_m}{2}\right)}{0.5} \implies \sin\left(\frac{60+D_m}{2}\right) = 0.5\sqrt{2} = \frac{\sqrt2}{2} = \sin45°

60+Dm2=45°  ⟹  60+Dm=90°  ⟹  Dm=30°\frac{60+D_m}{2} = 45° \implies 60+D_m = 90° \implies D_m = 30°

(c) Simple microscope — ray diagram and magnification

A simple microscope is just a single convex (converging) lens of short focal length, used to view small objects by placing them within the focal length of the lens, so the lens forms a virtual, erect, magnified image.

Ray diagram (described): The object O is placed between the lens's optical centre and its focus F (i.e. at a distance u<fu < f). Two rays are drawn from the top of the object: one travels parallel to the principal axis and, after refraction, appears to come from the focus F on the object's side; the other passes straight through the optical centre undeviated. Both refracted rays diverge on the object's side of the lens, and tracing them backward (with dashed lines), they appear to meet at a point behind the object — this locates the virtual, erect, magnified image I, at distance v from the lens (v is negative and |v| > u by sign convention, with u also negative).

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.