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Worked Examples · Example 4

Q.Find the equation of the perpendicular bisector of the line segment joining the points A(2,3)(2, 3) and B(6,−5)(6, -5).

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Find the midpoint of ABAB, the slope of ABAB, take the negative reciprocal for the perpendicular slope, then write the line through the midpoint.

Midpoint of (x1,y1),(x2,y2)(x_1,y_1),(x_2,y_2): (x1+x22,y1+y22)\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right). Slope: m=y2−y1x2−x1m=\dfrac{y_2-y_1}{x_2-x_1}. Perpendicular slope: −1m-\dfrac{1}{m}. Point-slope: y−y0=m⊥(x−x0)y-y_0=m_\perp(x-x_0).

  1. Given points. A(2,3)A(2,3), B(6,−5)B(6,-5).

  2. Find the midpoint MM of ABAB (the perpendicular bisector must pass through it):

M=(2+62,3+(−5)2)=(82,−22)=(4,−1)M = \left(\frac{2+6}{2}, \frac{3+(-5)}{2}\right) = \left(\frac{8}{2}, \frac{-2}{2}\right) = (4,-1)

  1. Find the slope of ABAB.

mAB=−5−36−2=−84=−2m_{AB} = \frac{-5-3}{6-2} = \frac{-8}{4} = -2

  1. Find the perpendicular slope (negative reciprocal, since the bisector is perpendicular to ABAB):

m⊥=−1mAB=−1−2=12m_\perp = -\frac{1}{m_{AB}} = -\frac{1}{-2} = \frac{1}{2}

  1. Write the line through M(4,−1)M(4,-1) with slope 12\tfrac12. y−(−1)=12(x−4)   ⟹   y+1=x−42y-(-1) = \frac12(x-4) \ \implies\ y+1 = \frac{x-4}{2} …

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