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Worked Examples · Example 29

Q.The cost function C(x) of a commodity is given as C(x)=2x(x+3x+2)+2C(x) = 2x\left(\dfrac{x+3}{x+2}\right) + 2. Prove that the marginal cost falls as the output 'x' increases.

Lakshadweep CbseNCERTSubjective· 3mImportance★★★★★
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Marginal cost is C′(x)C'(x); differentiate it again and show that derivative is negative, proving MC decreases with xx.

Marginal cost MC=dCdxMC=\dfrac{dC}{dx}. MC falls with xx if d(MC)dx=d2Cdx2<0\dfrac{d(MC)}{dx}=\dfrac{d^2C}{dx^2}<0.

  • C(x)C(x) = total cost, xx = output.
  1. C(x)=2x(x+3x+2)+2=2(x2+3x)x+2+2C(x)=2x\left(\dfrac{x+3}{x+2}\right)+2=\dfrac{2(x^2+3x)}{x+2}+2.
  2. Marginal cost by the quotient rule, with u=x2+3xu=x^2+3x, v=x+2v=x+2:

MC=C′(x)=2⋅(2x+3)(x+2)−(x2+3x)(1)(x+2)2.MC=C'(x)=2\cdot\frac{(2x+3)(x+2)-(x^2+3x)(1)}{(x+2)^2}.

  1. Simplify the numerator: (2x+3)(x+2)=2x2+7x+6(2x+3)(x+2)=2x^2+7x+6; subtract x2+3xx^2+3x:

2x2+7x+6−x2−3x=x2+4x+6=(x+2)2+2.2x^2+7x+6-x^2-3x=x^2+4x+6=(x+2)^2+2.

  1. Hence

MC=2[(x+2)2+2](x+2)2=2+4(x+2)2.MC=\frac{2\left[(x+2)^2+2\right]}{(x+2)^2}=2+\frac{4}{(x+2)^2}.

  1. Differentiate MC with respect to xx: …

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