Skip to content
Exercise 6 · Q2

Q.In a 1000 metres race, AA can give a start of 100 metres to BB and a start of 280 metres to CC. In the same race, how much start can BB give to CC?

Lakshadweep CbseNCERTSubjective· 3mImportance★★★★★
48% · 51/106 Questions
✓ Free question

Translate the starts into distances covered when AA finishes, form the B ⁣: ⁣CB\!:\!C ratio, and convert back to a start: 200200 m.

A start of ss metres means the runner needs to cover only (1000−s)(1000 - s) m; in the same race distances are proportional to speeds.

  1. AA gives BB a start of 100100 m: when AA runs 10001000 m, BB runs 1000−100=9001000-100 = 900 m.
  2. AA gives CC a start of 280280 m: when AA runs 10001000 m, CC runs 1000−280=7201000-280 = 720 m.
  3. Thus in the time AA runs 10001000 m, B=900B = 900 m and C=720C = 720 m, so CB=720900=45\dfrac{C}{B} = \dfrac{720}{900} = \dfrac{4}{5}.
  4. When BB runs 10001000 m, CC runs 1000×720900=8001000 \times \dfrac{720}{900} = 800 m.
  5. So BB finishes 1000−800=2001000-800 = 200 m ahead of CC; i.e. BB can give CC a start of 200200 m.

Check: 720900=0.8\dfrac{720}{900} = 0.8 and 1000×0.8=8001000\times0.8 = 800, giving a start of 200200 m ✓.

✓Final answer

In the same 10001000 m race, BB can give CC a start of 200200 metres.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.