Q.Identify A and B in the following reaction sequence: 2-(2-chloroethyl)cyclohexan-1-one (a cyclohexanone ring carrying a –CH2CH2Cl side chain on the carbon next to the C=O) reacts with KCN to give A; A is then treated with H2/Pd to give B.
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Start your 14-day free trial to unlock the full solution →Cyanide substitutes the chloride to make a nitrile (A); catalytic hydrogenation reduces that nitrile to a primary amine (B). The ketone is retained, giving a δ-amino ketone that can cyclise.
Step 1 – Nucleophilic substitution (A)
The cyanide ion (from KCN) is a good nucleophile and displaces chloride from the primary –CH2–Cl end of the side chain by SN2:
–CH2CH2Cl + KCN → –CH2CH2CN + KCl.
So A = 2-(2-cyanoethyl)cyclohexan-1-one (the cyclohexanone now carries a –CH2CH2CN side chain). One carbon is added to the chain.
Step 2 – Reduction of the nitrile (B)
H2 over Pd reduces the nitrile group to a primary amine:
–CH2CH2C≡N + 2 H2 → –CH2CH2CH2NH2.
The ketone C=O is not reduced under H2/Pd. So B = 2-(3-aminopropyl)cyclohexan-1-one.
Note (enrichment) …
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