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Worked Examples · Example 10

Q.Find the simple interest on ₹6,000 at 8% per annum for 3 years, and the amount payable at the end of the period.

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With P=6000P=6000, r=8r=8, n=3n=3:

SI=P r n100=6000×8×3100=144000100=₹1,440.\text{SI}=\frac{P\,r\,n}{100}=\frac{6000\times8\times3}{100}=\frac{144000}{100}=₹1{,}440.

The amount is principal plus interest:

Amount=P+SI=6000+1440=₹7,440.\text{Amount}=P+\text{SI}=6000+1440=₹7{,}440. …

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