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Exercises · Q14

Q.Find the coefficient of variation for the data: 8,10,12,14,168, 10, 12, 14, 16.

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Mean: xˉ=8+10+12+14+165=605=12\bar{x} = \dfrac{8 + 10 + 12 + 14 + 16}{5} = \dfrac{60}{5} = 12.

Standard deviation: squared deviations from 1212 are 16,4,0,4,1616, 4, 0, 4, 16, summing to 4040, so

σ2=405=8,σ=8=22≈2.83.\sigma^2 = \frac{40}{5} = 8, \qquad \sigma = \sqrt{8} = 2\sqrt{2} \approx 2.83.

Coefficient of variation:

C.V.=σxˉ×100=2.8312×100≈23.57%.\text{C.V.} = \frac{\sigma}{\bar{x}}\times 100 = \frac{2.83}{12}\times 100 \approx 23.57\%. …

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