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Answer in one sentence · Q41

Q.Why is the O2 molecule paramagnetic?

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Step 1. Recall O2's MO configuration (section 5.5.6). (σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(σ2pz)2(π2px)2(π2py)2(π∗2px)1(π∗2py)1(\sigma1s)^2(\sigma^*1s)^2(\sigma2s)^2(\sigma^*2s)^2(\sigma2p_z)^2(\pi2p_x)^2(\pi2p_y)^2(\pi^*2p_x)^1(\pi^*2p_y)^1.

Step 2. Identify the unpaired electrons. The final two electrons occupy the two degenerate π∗2px\pi^*2p_x and π∗2py\pi^*2p_y orbitals SINGLY (one electron in each), rather than both pairing up in just one of them. …

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