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Chemistry · Ch 15 — Hydrocarbons

Preparation of alkenes

15.2.2

Preparation of alkenes

The most industrially important alkenes -- ethene, propene, and buta-1,3-diene -- along with all alkenes up to four carbons, can be obtained in pure form from petroleum products; ethene specifically is produced from natural gas and crude oil by the cracking process already met in section 15.1.5. In the laboratory, alkenes are chiefly made by 1,2-elimination reactions, in which two atoms or groups are removed from two adjacent carbon atoms, converting the sp3-sp3 single bond between them into an sp2-sp2 double bond; when the atom removed from the adjacent (beta) carbon is a hydrogen, the reaction is called a beta-elimination. The most common such reaction is dehydrohalogenation of an alkyl halide: boiling the alkyl halide with a hot, concentrated ALCOHOLIC solution of a strong base such as KOH or NaOH removes H (from the beta-carbon) and X (from the alpha-carbon, the one that originally carried the halogen) together as water and the base's halide salt, leaving the alkene. When more than one beta-hydrogen is available (as in 2-chlorobutane, which can eliminate toward either C1 or C3), Saytzeff's rule predicts that the major product is the MORE substituted, more stable alkene -- 2-chlorobutane gives 80% but-2-ene against only 20% but-1-ene -- and correspondingly, the ease of dehydrohalogenation of the starting alkyl halide itself follows tertiary > secondary > primary. A second elimination route is dehydration of an alcohol: heating the alcohol with concentrated sulphuric acid removes -OH from the alpha-carbon and H from a beta-carbon as water, and just as with alkyl halides, the ease of dehydration follows tertiary > secondary > primary, so a tertiary alcohol dehydrates under far milder acid concentration and temperature (e.g. 20% H2SO4 at 363 K for 2-methylpropan-2-ol) than a primary one (75% H2SO4 at 413 K for butan-1-ol). A third elimination route is dehalogenation of a vicinal dihalide (two halogens on adjacent carbons): heating with zinc metal removes both halogens together as ZnX2, regenerating the alkene -- 1,2-dibromoethane gives ethene, and 1,2-dibromopropane gives propene. Alkenes can also be made by an ADDITION reaction rather than an elimination: partial ( …

Misc Saytzeff-ruleSaytzeff's rule and the ease of elimination/formation of alkenes

Worked out. 1,2-elimination removes two atoms/groups from adjacent carbons, converting an sp3-sp3 single bond into an sp2-sp2 double bond; when the leaving atom is halogen and hydrogen it is called dehydrohalogenation, with the halogen-bearing carbon called the alpha-carbon and the adjacent hydrogen-losing carbon the beta-carbon. Example: 2-chlorobutane with hot alcoholic KOH gives mainly but-2-ene (80%) and only 20% but-1-ene, because Saytzeff's rule states that the preferred elimination product is the alkene with the greater number of alkyl groups on the doubly-bonded carbons (the more substituted, more stable alkene). Consistent with this, the ease of dehydrohalogenation of alkyl halides follows tertiary > secondary > primary, the ease of dehydration of alcohols follows the same order, and the overall stability/ease-of-formation order of …

Misc Dehydration-examplesRegioselectivity in acid-catalysed dehydration of alcohols

Worked out. Dehydration is a beta-elimination: the -OH leaves the alpha-carbon and an H leaves an adjacent beta-carbon, needing progressively milder acid/temperature as the alcohol becomes more substituted. Butan-1-ol (a primary alcohol) needs 75% H2SO4 at 413 K to give but-1-ene (as the main product) plus water. A secondary alcohol under 60% H2SO4 at 373 K gives mainly but-2-ene (major) with some but-1-ene (minor). 2-Methylpropan-2-ol (a tertiary alcohol) dehydrates with only 20% H2SO4 at 363 K to give 2-methylprop-1-ene plus water -- the more substituted the alcohol, the milder the conditions needed, mirroring the tertiary > secondary > pri …

Misc Dehalogenation-LindlarDehalogenation of vicinal dihalides and partial reduction of alkynes

Worked out. A vicinal dihalide (two halogens on adjacent carbons) reacts with zinc metal to eliminate both halogens and form the alkene plus ZnX2: 1,2-dibromoethane with Zn gives ethene plus ZnBr2, and 1,2-dibromopropane with Zn gives propene plus ZnBr2. Separately, an alkyne's C-triple-bond-C can be partially reduced to a C=C double bond using a calculated amount of H2 over Lindlar's catalyst (palladium on charcoal, partially deactivated with quinoline or a sulfur compound); this route gives specifically the cis-alkene. The trans-alkene, by contrast, is obtained by reducing the same alkyne with sodium metal dissolved in …