Chemistry · Ch 1 — Some Basic Concepts of Chemistry
Average Atomic Mass
Average Atomic Mass
Most elements, as they actually occur in nature, exist not as a single, uniform kind of atom but as a mixture of two or more isotopes — atoms of the same element that carry different individual atomic masses (because they have differing numbers of neutrons in the nucleus, despite having the same number of protons). Since any real, naturally-occurring sample of the element contains all of its isotopes mixed together in fixed natural proportions, the 'atomic mass' actually assigned to that element must be a WEIGHTED AVERAGE across all of its isotopes — weighted according to each isotope's relative abundance, i.e. its percentage occurrence in nature — and this weighted value is what is called the element's average atomic mass. Carbon is a worked example of this in the source text: it occurs naturally as a mixture of three isotopes (carbon-12, carbon-13 and a trace of carbon-14), each with its own atomic mass and relative abundance (see the accompanying isotope table), and combining these using the weighted-average method gives an average atomic mass of 12.011 u for carbon as a whole — which is precisely the value printed for carbon in the periodic table, since periodic-table atomic masses are always these average atomic masses, not the mass of any single isotope. For everyday convenience, this average is ofte …
Isotope | Atomic mass (u) | Relative Abundance (%)
12C | 12.00000 | 98.892
13C | 13.00335 | 1.108
14C | 14.00317 | 2 x 10^-10
Weighted average atomic mass of carbon = (12.00000)(98.892/100) + (13.00335)(1.108/100) + (14.00317)(2x10^-10/100) = 12.011 u, which is the value a …
Element | Isotopes | Average atomic mass | Rounded off atomic mass
Carbon | 12C, 13C, 14C | 12.011 u | 12.0 u
Nitrogen | 14N, 15N | 14.007 u | 14.0 u
Oxygen | 16O, 17O, 18O | 15.999 u | 16.0 u
Chlorine | 35Cl, 37Cl | 35.453 u | 35.5 u
Bromine | 79Br, 81Br | 79.904 u | 79.9 u …
Worked out. Problem: calculate the average atomic mass of neon from its isotopic data — 20Ne (mass 19.9924 u, abundance 90.92%), 21Ne (mass 20.9940 u, abundance 0.26%), 22Ne (mass 21.9914 u, abundance 8.82%). Solution (own words): multiply each isotope's atomic mass by its percentage abundance, add the three products together, then divide by 100 (since the abundances are given as percentages): [(19.9924 x 90.92) + (20.9940 x 0.26) + (21.9914 x 8.82)] divided by 100 works out to 20.1707 u, i.e. about 20.17 u. This is exactly the same weighted-average method the main text uses for carbon's three isotopes, ap …