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Solve problems · Q45

Q.Calculate the mass of potassium chlorate required to liberate 6.72 dm3 of oxygen at STP. Molar mass of KClO3 is 122.5 g mol-1. (Ans. 24.5 g)

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Step 1. Decomposition reaction: 2 KClO3 → 2 KCl + 3 O2.

Step 2. Moles of O2 needed = volume at STP / molar volume = 6.72 dm3 / 22.4 dm3 mol-1 = 0.3 mol. …

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