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Exercise 1.1 · Q53

Q.Show that 7+3 i7−3 i+7−3 i7+3 i\dfrac{7+\sqrt3\,i}{7-\sqrt3\,i}+\dfrac{7-\sqrt3\,i}{7+\sqrt3\,i} is real.

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Let u=7+3 iu=7+\sqrt3\,i. The expression is uuˉ+uˉu=u2+uˉ2uuˉ\dfrac{u}{\bar u}+\dfrac{\bar u}{u}=\dfrac{u^2+\bar u^2}{u\bar u}. The denominator uuˉ=∣u∣2=72+(3)2=49+3=52u\bar u=|u|^2=7^2+(\sqrt3)^2=49+3=52. The numerator: u2=(7+3 i)2=49+143 i+3i2=46+143 iu^2=(7+\sqrt3\,i)^2=49+14\sqrt3\,i+3i^2=46+14\sqrt3\,i, and uˉ2=46−143 i\bar u^2=46-14\sqrt3\,i; adding gives 9292. So the value is 9252=2313\dfrac{92}{52}=\dfrac{23}{13}, wh …

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