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Exercise 1.1 · Q23

Q.Express the following in the form of a+iba+ib, a,b∈Ra,b\in\mathbb{R}, i=−1i=\sqrt{-1}. State the values of aa and bb : (1+i)−3(1+i)^{-3}

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(1+i)−3=1(1+i)3(1+i)^{-3}=\dfrac{1}{(1+i)^3}. First, (1+i)2=1+2i+i2=2i(1+i)^2=1+2i+i^2=2i, so (1+i)3=(1+i)2(1+i)=2i(1+i)=2i+2i2=−2+2i(1+i)^3=(1+i)^2(1+i)=2i(1+i)=2i+2i^2=-2+2i. So the expression is 1−2+2i=1−2(1−i)\dfrac{1}{-2+2i}=\dfrac{1}{-2(1-i)}. Multiply numerator and denominator by 1+i1+i: $\dfrac{1+i}{-2(1-i)(1+i)}=\dfrac{1+i}{-2(1+ …

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