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EXERCISE 6.2 · Q121

Q.Solve the following for xx, where ∣x∣|x| is the modulus function, [x][x] is the greatest integer function, {x}\{x\} is the fractional part function: ∣x−4∣+∣x−2∣=3|x-4|+|x-2|=3.

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Critical points at x=2,4x=2,4.

Case x<2x<2: ∣x−4∣+∣x−2∣=(4−x)+(2−x)=6−2x=3  ⟹  x=1.5|x-4|+|x-2|=(4-x)+(2-x)=6-2x=3 \implies x=1.5 (valid, <2<2).

Case 2≤x≤42\le x\le4: (4−x)+(x−2)=2=3(4-x)+(x-2)=2=3 — impossible, no solution here. …

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