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MISCELLANEOUS EXERCISE 6 (I) · Q130

Q.If log⁡(5x−9)−log⁡(x+3)=log⁡2\log(5x-9)-\log(x+3)=\log 2 then x=…x=\ldots (A) 33 (B) 55 (C) 22 (D) 77

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log⁡(5x−9)−log⁡(x+3)=log⁡2  ⟹  log⁡(5x−9x+3)=log⁡2  ⟹  5x−9x+3=2\log(5x-9)-\log(x+3)=\log2 \implies \log\left(\dfrac{5x-9}{x+3}\right)=\log2 \implies \dfrac{5x-9}{x+3}=2.

5x−9=2x+6  ⟹  3x=15  ⟹  x=55x-9=2x+6 \implies 3x=15 \implies x=5.

Domain check: 5x−9>05x-9>0 (x>1.8x>1.8) and x+3>0x+3>0 (x>−3x>-3); x=5x=5 satisfies both.

✓Final answer

(B) 55

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