Skip to content
Exercise 8.2 · Q13

Q.The mean of 5 observations is 4.8 and the variance is 6.56. If three of the five observations are 1, 3 and 8, find the other two observations.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
24% · 13/55 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: With n=5n=5 and mean 4.84.8, the total of all five observations is ∑xi=5(4.8)=24\sum x_i = 5(4.8)=24. Three are 1, 3, 8 (sum =12=12), so the other two (call them a,ba,b) satisfy a+b=24−12=12a+b = 24-12=12.

Step 2: With variance 6.566.56, ∑xi2=n(Var+xˉ2)=5(6.56+4.82)=5(6.56+23.04)=5(29.6)=148\sum x_i^2 = n(\text{Var}+\bar{x}^2) = 5(6.56+4.8^2)=5(6.56+23.04)=5(29.6)=148. The three known observations contribute 12+32+82=1+9+64=741^2+3^2+8^2=1+9+64=74, so a2+b2=148−74=74a^2+b^2=148-74=74. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.