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Exercise 8.3 · Q15
Q.

For a certain data, following information is available.

XY
Mean1317
S. D.32
Size2030

Obtain the combined standard deviation.

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✓ Free question

Step 1: xˉc=20(13)+30(17)50=260+51050=77050=15.4\bar{x}_c = \dfrac{20(13)+30(17)}{50}=\dfrac{260+510}{50}=\dfrac{770}{50}=15.4.

Step 2: d1=13−15.4=−2.4d_1=13-15.4=-2.4 and d2=17−15.4=1.6d_2=17-15.4=1.6.

Step 3: σc2=20(32+2.42)+30(22+1.62)50=20(14.76)+30(6.56)50=295.2+196.850=49250=9.84\sigma_c^2 = \dfrac{20(3^2+2.4^2)+30(2^2+1.6^2)}{50}=\dfrac{20(14.76)+30(6.56)}{50}=\dfrac{295.2+196.8}{50}=\dfrac{492}{50}=9.84.

Step 4: σc=9.84≈3.14\sigma_c = \sqrt{9.84} \approx 3.14.

✓Final answer

Combined S.D. ≈3.14\approx 3.14

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