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Exercise 8.3 · Q16

Q.Calculate coefficient of variation of marks secured by a student in the exam, where the marks are: 85, 91, 96, 88, 98, 82

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✓ Free question

Step 1: ∑xi=85+91+96+88+98+82=540\sum x_i = 85+91+96+88+98+82=540, n=6n=6, so xˉ=540/6=90\bar{x}=540/6=90.

Step 2: Deviations from mean: −5,1,6,−2,8,−8-5,1,6,-2,8,-8; their squares 25,1,36,4,64,6425,1,36,4,64,64 sum to 194194.

Step 3: Var(X)=194/6≈32.33\text{Var}(X)=194/6\approx32.33, so σ=32.33≈5.69\sigma=\sqrt{32.33}\approx5.69.

Step 4: C.V.=100×σ/xˉ=100×5.69/90≈6.32%\text{C.V.} = 100\times\sigma/\bar{x} = 100\times5.69/90 \approx 6.32\%.

✓Final answer

C.V. ≈6.32%\approx 6.32\%

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