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EXERCISE 3.6 · Q127

Q.Find the value of 20C16−19C16{}^{20}C_{16} - {}^{19}C_{16}

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By Pascal's Rule, 20C16=19C16+19C15{}^{20}C_{16}={}^{19}C_{16}+{}^{19}C_{15}, so 20C16−19C16=19C15{}^{20}C_{16}-{}^{19}C_{16}={}^{19}C_{15}. Evaluating: ${}^{19}C_{15}={}^{19}C_4=\dfrac{19\times18\times17\ …

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