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Mathematics · Ch 9 — Probability

Formula for Conditional Probability

9.3.2

Formula for Conditional Probability

The two worked examples in the previous section suggest a general shortcut: instead of listing the reduced sample space every time, conditional probability can be written directly in terms of ordinary probabilities. For a finite sample space SS with equally likely outcomes, once event BB is known to have occurred, the effective sample space shrinks to the n(B)n(B) outcomes of BB (the reduced sample space). Among those, only the outcomes that also belong to AA - namely the n(A∩B)n(A\cap B) outcomes in A∩BA\cap B - are favourable for AA. So by the classical definition applied to this reduced space, P(A/B)=n(A∩B)n(B)=n(A∩B)/n(S)n(B)/n(S)=P(A∩B)P(B),P(B)≠0.P(A/B)=\frac{n(A\cap B)}{n(B)}=\frac{n(A\cap B)/n(S)}{n(B)/n(S)}=\frac{P(A\cap B)}{P(B)},\qquad P(B)\ne 0. By the same reasoning with the roles of AA and BB swapped, P(B/A)=P(A∩B)P(A),P(A)≠0.P(B/A)=\frac{P(A\cap B)}{P(A)},\qquad P(A)\ne 0. …

Misc Ex1Single die - number less than 4 given it is odd

Worked out. Computes P(A) and P(A intersect B) directly by listing outcomes, then applies the conditional-probability formula. Working through this worked example after reading the theory above helps consolidate the method before attempting the exercise questions that follow it in the textbook. …

Misc Ex2Finding P(A/B) and P(A union B) from P(A'), P(B), P(B/A)

Worked out. Works backward from the complement of A and the conditional probability formula to find the intersection, then the reverse conditional probability, then the union via the addition theorem. …