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EXERCISE 2.1 · Q20

Q.The numbers 3,x3, x and x+6x+6 are in G.P. Find

(i) xx,
(ii) 20th term,
(iii) nnth term.
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For 3,x,x+63,x,x+6 in G.P.: x2=3(x+6)=3x+18⇒x2−3x−18=0⇒(x−6)(x+3)=0⇒x=6x^2=3(x+6)=3x+18 \Rightarrow x^2-3x-18=0 \Rightarrow (x-6)(x+3)=0 \Rightarrow x=6 or x=−3x=-3. Case x=6x=6: sequence 3,6,12,…3,6,12,\ldots, a=3,r=2a=3,r=2; t20=3⋅219=1572864t_{20}=3\cdot2^{19}=1572864, tn=3⋅2n−1t_n=3\cdot2^{n-1}. Case x=−3x=-3: sequence 3,−3,3,…3,-3,3,\ldots, a=3,r=−1a=3,r=-1; $t_{20}=3(-1)^{19}= …

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