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EXERCISE 2.1 · Q22

Q.The numbers x−6,2xx-6, 2x and x2x^2 are in G.P. Find

(i) xx
(ii) 1st term
(iii) nnth term.
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For x−6,2x,x2x-6, 2x, x^2 in G.P.: (2x)2=(x−6)x2⇒4x2=x3−6x2⇒x3−10x2=0⇒x2(x−10)=0⇒x=0(2x)^2=(x-6)x^2 \Rightarrow 4x^2=x^3-6x^2 \Rightarrow x^3-10x^2=0 \Rightarrow x^2(x-10)=0 \Rightarrow x=0 or x=10x=10. x=0x=0 gives terms −6,0,0-6,0,0, which is degenerate (a G.P. term cannot be 0), so x=10x=10. Te …

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