Skip to content
Exercise 5.2 · Q57

Q.If (x+13,y3−1)=(12,32)\left(x + \dfrac{1}{3}, \dfrac{y}{3} - 1\right) = \left(\dfrac{1}{2}, \dfrac{3}{2}\right), find x and y.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
49% · 57/117 Questions
✓ Free question

Equate first components: x+13=12x+\frac{1}{3} = \frac{1}{2}, so x=12−13=3−26=16x = \frac{1}{2}-\frac{1}{3} = \frac{3-2}{6} = \frac{1}{6}. Equate second components: y3−1=32\frac{y}{3}-1 = \frac{3}{2}, so y3=32+1=52\frac{y}{3} = \frac{3}{2}+1 = \frac{5}{2}, giving y=3×52=152y = 3\times\frac{5}{2} = \frac{15}{2}.

✓Final answer

x = \dfrac{1}{6}, ; y = \dfrac{15}{2}

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.