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Exercise 5.2 · Q76

Q.[Activity] Identify whether the following relation is reflexive, symmetric, and transitive: R = {(a,b) : a,b ∈ N, a² − 4ab + 3b² = 0}.

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Factor the condition: a2−4ab+3b2=(a−b)(a−3b)=0a^2-4ab+3b^2 = (a-b)(a-3b) = 0, so the pair (a,b) satisfies R exactly when a=ba=b or a=3ba=3b. Reflexive: taking a=ba=b always makes (a−b)(a−3b)=0⋅(−2a)=0(a-b)(a-3b) = 0\cdot(-2a) = 0, so (a,a)∈R(a,a)\in R for every a — reflexive. Symmetric: take (3,1)∈R(3,1)\in R since 3=3(1)3=3(1); is (1,3)∈R(1,3)\in R? That needs 1=31=3 or 1=3(3)=91=3(3)=9, neither true — so NOT symmetric. Transitive: take (9,3)∈R(9,3)\in R (since 9=3×39=3\times3) and (3,1)∈R(3,1)\in R (since …

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