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Physics · Ch 10 — Electrostatics

Couple Acting on an Electric Dipole in a Uniform Electric Field

10.9.1

Couple Acting on an Electric Dipole in a Uniform Electric Field

Consider an electric dipole -- charges −q-q at point A and +q+q at point B, separated by 2l2l -- placed in a UNIFORM external electric field E⃗\vec{E}, with the dipole's axis making some angle θ\theta with the direction of the field (Fig. 10.19a).

The force acting on the negative charge at A is F⃗A=−qE⃗\vec{F}_A=-q\vec{E}, directed OPPOSITE to the field; the force acting on the positive charge at B is F⃗B=+qE⃗\vec{F}_B=+q\vec{E}, directed ALONG the field. Since F⃗A=−F⃗B\vec{F}_A=-\vec{F}_B (equal magnitude, opposite direction), but these two forces act at two DIFFERENT points (A and B, separated by some perpendicular distance d between their lines of action), they do NOT cancel out to give zero net effect -- instead, together they form a COUPLE (Fig. 10.19b). The turning effect (moment) of a couple is called TORQUE, defined generally as τ=(perpendicular distance between the two forces)×(magnitude of each force).\tau=(\text{perpendicular distance between the two forces})\times(\text{magnitude of each force}).

Working out this perpendicular distance for the dipole geometry (using the projection of BA perpendicular to the field direction) gives τ=qE(2lsin⁡θ)=q(2l)Esin⁡θ.\tau=qE(2l\sin\theta)=q(2l)E\sin\theta. Recognising q(2l)=pq(2l)=p, the dipole moment, this simplifies to τ=pEsin⁡θ,\tau=pE\sin\theta, or, written in full vector form using the cross product, τ⃗=p⃗×E⃗.\vec{\tau}=\vec{p}\times\vec{E}. …

Figure 10.19Fig. 10.19 (a)-(b): A dipole in a uniform electric field, and the resulting couple

What this figure shows. Panel (a) shows an electric dipole (charges −q-q at A and +q+q at B, separated by 2l2l) placed inside a region of uniform, parallel, equally-spaced field lines E⃗\vec{E}, with the dipole's axis AB drawn tilted at an angle θ\theta to the direction of the field lines. Panel (b) redraws the same configuration with explicit force arrows: F⃗A=−qE⃗\vec{F}_A=-q\vec{E} shown at A pointing OPPOSITE to the field direction, and F⃗B=+qE⃗\vec{F}_B=+q\vec{E} shown at B pointing ALONG the field direction; these two equal-magnitude, oppositely-directed forces act at two different points (A and B) separated perpendicular distance d, together forming a COUPLE that rotates/tends to rotate the dipole to align its axis with the field -- the geometric basis …

Misc Ex.9Example 10.9: Charge on a dipole from its torque, length, angle and field

Worked out. An electric dipole of length 2l=2.02l=2.0 cm is placed with its axis at θ=30∘\theta=30^\circ to a uniform field E=105E=10^5 N/C, experiencing a torque of τ=1×10−3\tau=1\times10^{-3} N m. Using τ=qE(2l)sin⁡θ\tau=qE(2l)\sin\theta: 1×10−3=q×105×0.02×sin⁡30∘=q×105×0.02×0.5=q×10001\times10^{-3}=q\times10^5\times0.02\times\sin30^\circ=q\times10^5\times0.02\times0.5=q\times1000, giving q=1×10−3/1000=1×10−6 C=1 μCq=1\times10^{-3}/1000=1\times10^{-6}\,\text{C}=1\,\mu\text{C} -- a direct rearrangement of the torque formula to solve for the unknown charge magnitude given every other quantity in the r …