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Physics · Ch 1 — Units and Measurements

Combination of errors

1.8.2

Combination of errors

When an experiment involves several measured quantities that must be combined (added, multiplied, divided, or raised to a power) to compute a final result, it is essential to know how the individual errors of each measured quantity combine to determine the error in that final result. For example, when the resistance of a conductor is found using Ohm's law from separately measured potential difference and current, the errors in those two individual measurements combine to produce an overall error in the derived resistance.

  1. Errors in sum and in difference. Suppose two quantities AA and BB have measured values A±ΔAA \pm \Delta A and B±ΔBB \pm \Delta B. For their sum, Z=A+BZ = A + B: Z±ΔZ=(A±ΔA)+(B±ΔB)=(A+B)±ΔA±ΔBZ \pm \Delta Z = (A \pm \Delta A) + (B \pm \Delta B) = (A+B) \pm \Delta A \pm \Delta B, so ±ΔZ=±ΔA±ΔB\pm\Delta Z = \pm\Delta A \pm \Delta B. For their difference, Z=A−BZ = A - B: similarly Z±ΔZ=(A−B)±ΔA±ΔBZ \pm \Delta Z = (A-B) \pm \Delta A \pm \Delta B. In both cases there are four possible sign combinations for ΔZ\Delta Z (namely +ΔA−ΔB+\Delta A - \Delta B, +ΔA+ΔB+\Delta A + \Delta B, −ΔA−ΔB-\Delta A - \Delta B, −ΔA+ΔB-\Delta A + \Delta B), and the maximum possible value of ∣ΔZ∣|\Delta Z| in every case is ΔZ=ΔA+ΔB\Delta Z = \Delta A + \Delta B. So: whenever two quantities are added or subtracted, the maximum absolute error in the result is the sum of the absolute errors in the two individual quantities — errors never cancel when we want the worst-case bound.
  2. Errors in product and in division. Suppose Z=ABZ = AB, with measured values A±ΔAA \pm \Delta A and B±ΔBB \pm \Delta B. Then Z±ΔZ=(A±ΔA)(B±ΔB)=AB±AΔB±BΔA±ΔAΔBZ \pm \Delta Z = (A \pm \Delta A)(B \pm \Delta B) = AB \pm A\Delta B \pm B\Delta A \pm \Delta A \Delta B. Dividing the left side by ZZ and the (equal) right side by ABAB, and neglecting the tiny product term ΔA ΔB/AB\Delta A\, \Delta B / AB (since both ΔA/A\Delta A/A and ΔB/B\Delta B/B are small), gives the maximum relative error in ZZ as

    ΔZZ=ΔAA+ΔBB— (1.7)\dfrac{\Delta Z}{Z} = \dfrac{\Delta A}{A} + \dfrac{\Delta B}{B} \qquad \text{--- (1.7)}

    Exactly the same formula applies to division of two quantities. So: whenever two quantities are multiplied or divided, the maximum relative error in the result is the sum of the relative errors in each of the individual quantities.
  3. Errors due to a power (index) of a measured quantity. If Z=A3=A⋅A⋅AZ = A^3 = A \cdot A \cdot A, applying the product rule above three times over gives ΔZZ=ΔAA+ΔAA+ΔAA=3ΔAA\dfrac{\Delta Z}{Z} = \dfrac{\Delta A}{A} + \dfrac{\Delta A}{A} + \dfrac{\Delta A}{A} = 3\dfrac{\Delta A}{A} — the relative error is tripled. This generalises: for Z=AnZ = A^n,

    ΔZZ=nΔAA— (1.8)\dfrac{\Delta Z}{Z} = n\dfrac{\Delta A}{A} \qquad \text{--- (1.8)}

    and more generally still, for a quantity built from several measured factors each raised to its own power, Z=ApBqCrZ = \dfrac{A^p B^q}{C^r}, ΔZZ=pΔAA+qΔBB+rΔCC— (1.9)\dfrac{\Delta Z}{Z} = p\dfrac{\Delta A}{A} + q\dfrac{\Delta B}{B} + r\dfrac{\Delta C}{C} \qquad \text{--- (1.9)} …
Misc Ex 1.6Percentage error in volume from mass and density

Worked out. Worked example computing the maximum percentage error in the volume of an object, given its measured mass m = (5 ± 0.15) kg and density ρ = (5 ± 0.2) kg m^-3. Since volume = mass/density, the method applies the product-and-division error-combination rule from this section (percentage error in volume = percentage error in mass + percentage error in density) to the two given qu …

Misc Ex 1.7Percentage error in g from a simple pendulum's length and period

Worked out. Worked example finding the maximum percentage error in the acceleration due to gravity g, determined from a simple pendulum of length l = (100 ± 0.1) cm and time period T = (2 ± 0.01) s using T = 2π√(l/g). The method rearranges the pendulum formula to g = 4π²l/T², recognises that squaring T doubles its relative-error contribution (per the power rule of this section), and adds the percentage errors of l (with coefficient 1) and T (with coefficient 2) to get the percentage error in g o …