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Numerical · Q12

Q.The masses of two bodies are measured to be 15.7 ± 0.2 kg and 27.3 ± 0.3 kg. What is the total mass of the two and the error in it?

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Step 1. Total mass M=m1+m2=15.7 kg+27.3 kg=43.0 kgM = m_1 + m_2 = 15.7\ \text{kg} + 27.3\ \text{kg} = 43.0\ \text{kg}.

Step 2. By the sum-error rule (section 1.8.2a), the maximum absolute error in a sum is the sum of the individual absolute errors: ΔM=Δm1+Δm2=0.2 kg+0.3 kg=0.5 kg\Delta M = \Delta m_1 + \Delta m_2 = 0.2\ \text{kg} + 0.3\ \text{kg} = 0.5\ \text{kg}.

✓Final answer

Total mass = (43.0±0.5) kg(43.0 \pm 0.5)\ \text{kg}

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