Skip to content
Numerical · Q19

Q.In Ohm's experiments, the values of the unknown resistances were found to be 6.12 Ω, 6.09 Ω, 6.22 Ω, 6.15 Ω. Calculate the mean absolute error, relative error and percentage error in these measurements.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
70% · 19/27 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Mean =6.12+6.09+6.22+6.154=24.584=6.145 Ω= \dfrac{6.12+6.09+6.22+6.15}{4} = \dfrac{24.58}{4} = 6.145\ \Omega.

Step 2. Absolute errors: ∣6.12−6.145∣=0.025|6.12-6.145|=0.025, ∣6.09−6.145∣=0.055|6.09-6.145|=0.055, ∣6.22−6.145∣=0.075|6.22-6.145|=0.075, ∣6.15−6.145∣=0.005|6.15-6.145|=0.005 (all in Ω).

Step 3. Mean absolute error =0.025+0.055+0.075+0.0054=0.164=0.04 Ω= \dfrac{0.025+0.055+0.075+0.005}{4} = \dfrac{0.16}{4} = 0.04\ \Omega. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.