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Long Answer Questions · Q12

Q.State and explain the Law of Equi-Marginal Utility with a suitable numerical illustration showing the consumer's equilibrium.

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Statement of the Law. A consumer, with a fixed income to spend on two or more goods, obtains maximum total satisfaction when the marginal utility of the last rupee spent on each good is equal, and the whole of the income is spent — formally, MUxPx=MUyPy\dfrac{MU_x}{P_x} = \dfrac{MU_y}{P_y}, where each ratio is the marginal utility per rupee spent on that good.

Numerical illustration. Suppose a consumer has a fixed income of Rs 20, to be spent on goods X (price PxP_x = Rs 4) and Y (price PyP_y = Rs 2), with the following marginal utility schedules:

UnitsMUxMUx/PxMUyMUy/Py
140102412
23282010
3246168
4164126

Finding the equilibrium. The consumer compares MUx/PxMU_x/P_x and MUy/PyMU_y/P_y and, being rational, always spends the next rupee on whichever good currently offers the higher marginal utility per rupee, continuing until income is exhausted and the two ratios are equalised. At X = 3 units, Y = 4 units: MUx/Px=6MU_x/P_x = 6 and MUy/Py=6MU_y/P_y = 6 — equal, as the law requires. Checking the budget: 3×4+4×2=12+8=203 \times 4 + 4 \times 2 = 12 + 8 = 20, exactly equal to the given income of Rs 20. Both conditions of the law are satisfied simultaneously, so X = 3, Y = 4 is the consumer's equilibrium combination.

Why no other combination is better. Consider instead X = 4, Y = 2, which also costs Rs 20 (4×4+2×2=16+4=204 \times 4 + 2 \times 2 = 16 + 4 = 20): here MUx/Px=4MU_x/P_x = 4 but MUy/Py=10MU_y/P_y = 10. Since the last rupee spent on Y yields far more utility than the last rupee spent on X, the consumer is clearly not maximising total utility — shifting one rupee's worth of spending from X toward Y would raise total satisfaction. Only at X = 3, Y = 4, where the two ratios are exactly equal, is there no such profitable rearrangement possible, confirming it as the true point of consumer's equilibrium. …

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