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Exercises · Q11

Q.The demand function is x=40−5px = 40 - 5p, where xx is the quantity demanded at price pp (in ₹). Find the elasticity of demand at p=6p = 6 and interpret your result.

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Set up. Demand x=40−5px = 40 - 5p, so

dxdp=−5.\frac{dx}{dp} = -5.

Elasticity formula.

η=−px⋅dxdp=−px (−5)=5px.\eta = -\frac{p}{x}\cdot\frac{dx}{dp} = -\frac{p}{x}\,(-5) = \frac{5p}{x}.

Evaluate at p=6p = 6. First find the demand: x=40−5(6)=40−30=10x = 40 - 5(6) = 40 - 30 = 10. Then

η=5(6)10=3010=3.\eta = \frac{5(6)}{10} = \frac{30}{10} = 3.

Interpret. Since η=3>1\eta = 3 > 1, demand is elastic at p=6p = 6: a 1%1\% increase in price causes approximately a 3%3\% decrease in quantity demanded. Demand is very responsive to price, so raising the price here would reduce total revenue.

Dual check: the sign of dx/dp=−5dx/dp = -5 is negative (demand falls as price rises), and with the leading minus the elasticity comes out positive, η=3\eta = 3, as found. A quick proportional check — near p=6p = 6, raising price to p=6.06p = 6.06 (a 1%1\% rise) gives x=40−30.3=9.7x = 40 - 30.3 = 9.7, a fall of 0.30.3 from 1010, i.e. 3%3\% — consistent with η=3\eta = 3. ✓

✓Final answer

At p=6p = 6 the demand is x=10x = 10 and the elasticity is η=5(6)10=3\eta = \dfrac{5(6)}{10} = 3; since η>1\eta > 1, demand is elastic — quantity changes proportionally much more than price.

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