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Exercises · Q14

Q.The total cost of producing xx units is C(x)=3x2+12x+75C(x) = 3x^2 + 12x + 75 (in ₹). Find the output at which the average cost is minimum and the minimum average cost.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Average cost.

C‾(x)=C(x)x=3x2+12x+75x=3x+12+75x.\overline{C}(x) = \frac{C(x)}{x} = \frac{3x^2 + 12x + 75}{x} = 3x + 12 + \frac{75}{x}.

Minimise. Differentiate:

C‾′(x)=3−75x2.\overline{C}'(x) = 3 - \frac{75}{x^2}.

Set C‾′(x)=0\overline{C}'(x) = 0:

3−75x2=0 ⇒ x2=753=25 ⇒ x=5(x>0).3 - \frac{75}{x^2} = 0 \ \Rightarrow\ x^2 = \frac{75}{3} = 25 \ \Rightarrow\ x = 5 \quad (x > 0).

Confirm a minimum.

C‾′′(x)=150x3>0 for x>0,\overline{C}''(x) = \frac{150}{x^3} > 0 \text{ for } x > 0,

so x=5x = 5 gives a minimum.

Minimum average cost.

C‾(5)=3(5)+12+755=15+12+15=42.\overline{C}(5) = 3(5) + 12 + \frac{75}{5} = 15 + 12 + 15 = 42. …

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