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Question 19 of 32
Q.

A marketing manager has list of salesmen and territories. Considering the travelling cost of the salesmen and the nature of territory, the marketing manager estimates the total of cost per month (in thousand rupees) for each salesman in each territory. Suppose these amounts are as follows:

SalesmanTerritories
IIIIIIIVV
A1116181515
B719111317
C9614147
D1312171113
Find the assignment of salesman to territories that will result in minimum cost.
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2023Subjective· 4mImportance★★★★★
59% · 19/32 Questions
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Balance the 4×54\times5 matrix with a dummy salesman EE (all zeros), apply the Hungarian method, and obtain A→IA\to I, B→IIIB\to III, C→IIC\to II, D→IVD\to IV with VV unassigned; minimum cost =₹39,000= ₹39{,}000.

Cost matrix (thousand ₹) with a dummy row EE added to make it square:

IIIIIIIVV
A1116181515
B719111317
C9614147
D1312171113
E00000

Step 1 — Row reduction (subtract each row's minimum; row EE is already 00):

IIIIIIIVV
A05744
B0124610
C30881
D21602
E00000

Step 2 — Column reduction. Every column already contains a 00, so the matrix is unchanged.

Step 3 — Cover the zeros. The zeros can be covered by 44 lines (row EE; columns I, II, IV), which is fewer than 55, so we improve. Repeatedly subtracting the smallest uncovered entry from all uncovered cells and adding it at line-intersections (standard Hungarian iterations) finally produces a reduced matrix admitting one independent zero per row and column:

IIIIIIIVV
A02320

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