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Question 37 of 40

Q.The solution of dydx=1\frac{dy}{dx} = 1 is ______.

(a) x+y=cx + y = c
(b) xy=cxy = c
(c) x2+y2=cx^2 + y^2 = c
(d) y−x=cy - x = c
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026MCQ· 1mImportance★★★★★
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Integrate dydx=1\dfrac{dy}{dx}=1 directly to get y=x+cy = x + c, i.e. y−x=cy - x = c — option (iv).

The equation is already in variables-separable form:

dydx=1  ⇒  dy=dx.\frac{dy}{dx} = 1 \;\Rightarrow\; dy = dx.

Integrating both sides:

∫dy=∫dx  ⇒  y=x+c,\int dy = \int dx \;\Rightarrow\; y = x + c,

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